Question

a watermelon weighs 8,475 grams (g). a scale measured the weight with an error of 12% under the actual weight. what was the measured weight?

Explanation:

Step1: Determine the percentage of measured weight

The actual weight is 8,475 grams, and the scale measures 12% under the actual weight. So the measured weight is \(100\% - 12\% = 88\%\) of the actual weight. In decimal form, \(88\% = 0.88\).

Step2: Calculate the measured weight

Multiply the actual weight by the decimal representing the measured percentage: \(8475\times0.88\).
First, calculate \(8475\times0.8 = 6780\) and \(8475\times0.08 = 678\). Then add these two results: \(6780 + 678 = 7458\).

Answer:

The measured weight is 7458 grams.