Question

water has a specific heat of 4.186 j/g°c. how much heat is required to increase 10.0 g of water from 25.0°c to 30.0°c?
5.0 j
21 j
42 j
209 j

Explanation:

Step1: Identify the formula

The formula for heat is $Q = mc\Delta T$, where $Q$ is heat, $m$ is mass, $c$ is specific - heat, and $\Delta T$ is change in temperature.

Step2: Calculate the change in temperature

$\Delta T=T_2 - T_1=30.0^{\circ}C - 25.0^{\circ}C = 5.0^{\circ}C$

Step3: Substitute values into the formula

$m = 10.0\ g$, $c = 4.186\ J/g^{\circ}C$, $\Delta T = 5.0^{\circ}C$. Then $Q=mc\Delta T=(10.0\ g)\times(4.186\ J/g^{\circ}C)\times(5.0^{\circ}C)=209.3\ J\approx209\ J$

Answer:

D. 209 J