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the volume of the cereal box must be 192 \\text{ in.}^3. height: \\((x …

Question

the volume of the cereal box must be 192 \text{ in.}^3.

height: \\((x + 10)\\) \text{ in.}
width: \\((x - 4)\\) \text{ in.}
length: \\(x\\) \text{ in.}

polynomial equation: \\(x^3 + 6x^2 - 40x = 192\\)
solutions: \\(x = -8\\), \\(x = -4\\), and \\(x = 6\\)

in the context of this problem, which solutions to the polynomial equation can you eliminate because they do not make sense?
\\(x = -8\\)
\\(x = -4\\)
\\(x = 6\\)

what are the dimensions of the cereal box?
the length is in., the width is in., and the height is in.

Explanation:

Evaluate physical constraints on dimensions

$$ LATEXBLOCK0 $$

Determine valid solution

$$ LATEXBLOCK1 $$

Calculate dimensions

$$ LATEXBLOCK2 $$

Answer:

What are the dimensions of the cereal box?

The length is <blank>6</blank> in., the width is <blank>2</blank> in., and the height is <blank>16</blank> in.