Question

1. if the vertex angle of an isosceles triangle is 44° what are the two base angles?

Explanation:

Step1: Recall triangle angle sum

The sum of angles in a triangle is \(180^\circ\). For an isosceles triangle, the two base angles are equal. Let each base angle be \(x\).

Step2: Set up the equation

The vertex angle is \(44^\circ\), so the equation is \(44^\circ + x + x = 180^\circ\). Simplify to \(44^\circ + 2x = 180^\circ\).

Step3: Solve for \(x\)

Subtract \(44^\circ\) from both sides: \(2x = 180^\circ - 44^\circ = 136^\circ\). Then divide by 2: \(x = \frac{136^\circ}{2} = 68^\circ\).

Answer:

\(68^\circ\) (corresponding to the option with \(68^\circ\))