QUESTION IMAGE
Question
for the vectors u and w with angle θ between them sketch the resultant. |u|=25, |w|=12, θ=28° choose the correct sketch of the resultant below. a. image of vector diagram b. image of vector diagram c. image of vector diagram
Step1: Recall Vector Addition
To find the resultant of two vectors \( \mathbf{u} \) and \( \mathbf{w} \) with an angle \( \theta \) between them, we use the parallelogram law or the triangle law of vector addition. The triangle law states that if we place the tail of one vector at the head of the other, the resultant is the vector from the tail of the first to the head of the second. The parallelogram law states that the resultant is the diagonal of the parallelogram formed by the two vectors.
Step2: Analyze the Magnitudes and Angle
We know \( |\mathbf{u}| = 25 \), \( |\mathbf{w}| = 12 \), and \( \theta = 28^\circ \). The angle between \( \mathbf{u} \) and \( \mathbf{w} \) is \( 28^\circ \), so when sketching the resultant, we need to check the direction and the relative lengths.
Step3: Evaluate the Sketches
- Option A: The vectors \( \mathbf{w} \) and \( \mathbf{u} \) are placed tail - to - tail, and the resultant is drawn using the triangle law (from tail of \( \mathbf{w} \) to head of \( \mathbf{u} \) when \( \mathbf{w} \) is placed at tail of \( \mathbf{u} \)? Wait, no, in option A, we have \( \mathbf{w} \) with a small magnitude (since \( |\mathbf{w}| = 12 \) and \( |\mathbf{u}| = 25 \), \( \mathbf{w} \) should be shorter than \( \mathbf{u} \)) and \( \mathbf{u} \) longer. The angle between them is \( 28^\circ \), and the resultant is drawn correctly as the vector from the tail of \( \mathbf{w} \) to the head of \( \mathbf{u} \) when \( \mathbf{w} \) is placed at the tail of \( \mathbf{u} \)? Wait, no, let's re - examine. Wait, the length of \( \mathbf{u} \) is 25, \( \mathbf{w} \) is 12, so \( \mathbf{u} \) should be longer than \( \mathbf{w} \). In option A, \( \mathbf{u} \) is longer than \( \mathbf{w} \), the angle between them is \( 28^\circ \), and the resultant is the red vector. But wait, let's check the other options.
- Option B: The vectors are placed tail - to - tail, and the resultant is the diagonal of the parallelogram. But the length of \( \mathbf{w} \) and \( \mathbf{u} \) seem to be misrepresented ( \( \mathbf{w} \) looks almost as long as \( \mathbf{u} \), but \( |\mathbf{w}| = 12 \) and \( |\mathbf{u}| = 25 \), so \( \mathbf{w} \) should be shorter).
- Option C: The direction of the vectors and the resultant seem incorrect. The resultant should be in a direction that combines the two vectors.
Wait, actually, when using the triangle law, if we have vectors \( \mathbf{w} \) and \( \mathbf{u} \) with \( \mathbf{w} \) having a smaller magnitude (12) than \( \mathbf{u} \) (25), and an angle of \( 28^\circ \) between them, the correct sketch should show \( \mathbf{w} \) shorter than \( \mathbf{u} \) and the resultant vector. But looking at the options, in option A, \( \mathbf{w} \) is shorter than \( \mathbf{u} \), the angle between them is \( 28^\circ \), and the resultant is drawn as the vector from the tail of \( \mathbf{w} \) to the head of \( \mathbf{u} \) (when we place \( \mathbf{w} \) at the tail of \( \mathbf{u} \), but actually, the triangle law is: place the tail of \( \mathbf{w} \) at the head of \( \mathbf{u} \), then the resultant is from tail of \( \mathbf{u} \) to head of \( \mathbf{w} \)? No, I think I made a mistake. The correct way is: for vector addition \( \mathbf{u}+\mathbf{w} \), we can place the tail of \( \mathbf{w} \) at the head of \( \mathbf{u} \), then the resultant \( \mathbf{u}+\mathbf{w} \) is the vector from the tail of \( \mathbf{u} \) to the head of \( \mathbf{w} \). In option A, we have \( \mathbf{w} \) with a smaller length (since \( |\mathbf{w}| = 12 \),…
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A. The sketch with \( \mathbf{w} \) (shorter vector) and \( \mathbf{u} \) (longer vector) with an angle of \( 28^\circ \) between them, and the resultant vector drawn from the tail of \( \mathbf{w} \) to the head of \( \mathbf{u} \) (triangle law of vector addition).