Question

value: 3
solve for x.
\\(\sqrt{x + 8} - 5 = -2\\)
\\(\circ\\) a. \\(x=25\\)
\\(\circ\\) b. \\(x=9\\)
\\(\circ\\) c. \\(x=1\\)
\\(\circ\\) d. \\(x=41\\)

2/6

quiz 7.4.1 - solving radical equations
week 3 - assignment 8 of 13

Explanation:

Step1: Isolate the radical term

Add 5 to both sides:
$\sqrt{x+8} - 5 + 5 = -2 + 5$
$\sqrt{x+8} = 3$

Step2: Eliminate the square root

Square both sides:
$(\sqrt{x+8})^2 = 3^2$
$x + 8 = 9$

Step3: Solve for x

Subtract 8 from both sides:
$x + 8 - 8 = 9 - 8$
$x = 1$

Answer:

c. x=1