Question

uzzle #1
1: solve for a:
a - bc = d
2: solve for a:
ab + d = c
3: solve for a:
bc = ad
4: solve for a:
\frac{a}{dc} = b
answer choices
a: d + bc
b: \frac{cd}{b}
c: bcd
d: \frac{bc}{d}
e: \frac{c - d}{b}
f: b + cd
g: d - bc
h: \frac{b}{cd}
i: \frac{a + b}{c}
type the 4-letter code into the answer box. all caps, no spaces.

Explanation:

Problem 1: Solve for \( a \): \( a - bc = d \)

Step 1: Isolate \( a \)

To solve for \( a \), we add \( bc \) to both sides of the equation.
\( a - bc + bc = d + bc \)

Step 2: Simplify

Simplifying the left side (since \( -bc + bc = 0 \)), we get:
\( a = d + bc \)
Looking at the answer choices, this matches option A.

Problem 2: Solve for \( a \): \( ab + d = c \)

Step 1: Isolate the term with \( a \)

Subtract \( d \) from both sides of the equation:
\( ab + d - d = c - d \)
\( ab = c - d \)

Step 2: Solve for \( a \)

Divide both sides by \( b \) (assuming \( b
eq 0 \)):
\( a = \frac{c - d}{b} \)
This matches option E.

Problem 3: Solve for \( a \): \( bc = ad \)

Step 1: Solve for \( a \)

Divide both sides of the equation by \( d \) (assuming \( d
eq 0 \)):
\( a = \frac{bc}{d} \)
This matches option D.

Problem 4: Solve for \( a \): \( \frac{a}{dc} = b \)

Answer:

AEDC