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using place value to round decimals you can round decimals to many diff…

Question

using place value to round decimals
you can round decimals to many different place values
example 26.284
tenths
26.289
step 1
identify the place value you want to round to.
**underline the digit
step 2
look at the digit in the place value to the right
**circle it. if this number is......
0 - 4 → round down \0 to 4... do no more!\
5 - 9 → round up \5 to 9... climb the vine!\
26.289
the 8 tells you to
round up to 26.3
round each number below to the nearest whole
ex 17.394 17 ex 4.89 5
1 13.65 2 72 3 54.092
4 28.204 5 6.92 6 3.4
round each number below to the nearest tenth
ex 26.394 26.4 ex 8.52 8.5
7 5.28 8 3.610 9 4.7251
10 44.095 11 8.97 12 37.43
round each number below to the nearest hundredth
ex 2.892 2.89 ex 80.1465 80.15
13 3.762 14 75.149 15 6.723
16 6.9082 17 40.615 18 12.3194

Explanation:

Step1: Round to the nearest whole number

For \(13.65\), the digit in the tenths place is \(6\) (\(6\geq5\)), so we round up. \(13 + 1=14\).
For \(7.2\), the digit in the tenths place is \(2\) (\(2\lt5\)), so we round down. It remains \(7\).
For \(54.092\), the digit in the tenths place is \(0\) (\(0\lt5\)), so we round down. It remains \(54\).
For \(28.204\), the digit in the tenths place is \(2\) (\(2\lt5\)), so we round down. It remains \(28\).
For \(6.92\), the digit in the tenths place is \(9\) (\(9\geq5\)), so we round up. \(6 + 1=7\).
For \(3.4\), the digit in the tenths place is \(4\) (\(4\lt5\)), so we round down. It remains \(3\).

Step2: Round to the nearest tenth

For \(5.28\), the digit in the hundredths place is \(8\) (\(8\geq5\)), so we round up. \(5.2+0.1 = 5.3\).
For \(3.610\), the digit in the hundredths place is \(1\) (\(1\lt5\)), so we round down. It remains \(3.6\).
For \(4.7251\), the digit in the hundredths place is \(2\) (\(2\lt5\)), so we round down. It remains \(4.7\).
For \(44.095\), the digit in the hundredths place is \(9\) (\(9\geq5\)), so we round up. \(44.0 + 0.1=44.1\).
For \(8.97\), the digit in the hundredths place is \(7\) (\(7\geq5\)), so we round up. \(8.9+0.1 = 9.0\).
For \(37.43\), the digit in the hundredths place is \(3\) (\(3\lt5\)), so we round down. It remains \(37.4\).

Step3: Round to the nearest hundredth

For \(3.762\), the digit in the thousandths place is \(2\) (\(2\lt5\)), so we round down. It remains \(3.76\).
For \(75.49\), the digit in the thousandths place is \(0\) (assuming it's \(75.490\) for the purpose of rounding rules), so we round down. It remains \(75.49\).
For \(6.723\), the digit in the thousandths place is \(3\) (\(3\lt5\)), so we round down. It remains \(6.72\).
For \(6.9082\), the digit in the thousandths place is \(8\) (\(8\geq5\)), so we round up. \(6.90+0.01 = 6.91\).
For \(40.615\), the digit in the thousandths place is \(5\) (\(5\geq5\)), so we round up. \(40.61+0.01 = 40.62\).
For \(12.3194\), the digit in the thousandths place is \(9\) (\(9\geq5\)), so we round up. \(12.31+0.01 = 12.32\).

Answer:

  1. \(14\)
  2. \(7\)
  3. \(54\)
  4. \(28\)
  5. \(7\)
  6. \(3\)
  7. \(5.3\)
  8. \(3.6\)
  9. \(4.7\)
  10. \(44.1\)
  11. \(9.0\)
  12. \(37.4\)
  13. \(3.76\)
  14. \(75.49\)
  15. \(6.72\)
  16. \(6.91\)
  17. \(40.62\)
  18. \(12.32\)