QUESTION IMAGE
Question
using the image provided, which of the following describes the side lengths of the triangle from least to greatest?
○ st < rs < rt
○ rt < ts < rs
○ sr < ts < rt
○ none of these
Step1: Find the third angle
In triangle \( RST \), the sum of angles in a triangle is \( 180^\circ \). Given \( \angle S = 70^\circ \), \( \angle R = 68^\circ \), so \( \angle T = 180 - 70 - 68 = 42^\circ \).
Step2: Relate angles to sides
In a triangle, the larger the angle, the longer the opposite side.
- Opposite \( \angle T = 42^\circ \) is \( RS \).
- Opposite \( \angle R = 68^\circ \) is \( ST \).
- Opposite \( \angle S = 70^\circ \) is \( RT \).
So the order of angles from least to greatest: \( \angle T (42^\circ) < \angle R (68^\circ) < \angle S (70^\circ) \). Thus, the order of sides (opposite these angles) from least to greatest: \( RS < ST < RT \)? Wait, no, wait. Wait, angle at T is 42, opposite RS; angle at R is 68, opposite ST; angle at S is 70, opposite RT. So angle order: \( 42^\circ (\angle T) < 68^\circ (\angle R) < 70^\circ (\angle S) \), so side order (opposite): \( RS < ST < RT \)? Wait, no, the options are about \( ST \), \( RS \), \( RT \). Wait the first option is \( ST < RS < RT \)? Wait no, let's re - check. Wait angle at T is 42, so side opposite (RS) is shortest. Angle at R is 68, side opposite (ST) is next. Angle at S is 70, side opposite (RT) is longest. So the order of sides from least to greatest: \( RS < ST < RT \)? Wait the options:
First option: \( ST < RS < RT \) – no.
Wait wait, maybe I mixed up. Let's label the triangle: vertices R, S, T. Angles: at S is 70, at R is 68, at T is 42. So:
- Side opposite \( \angle T \) (42°) is \( RS \).
- Side opposite \( \angle R \) (68°) is \( ST \).
- Side opposite \( \angle S \) (70°) is \( RT \).
So angle sizes: \( \angle T = 42^\circ < \angle R = 68^\circ < \angle S = 70^\circ \). Therefore, side lengths (opposite angles): \( RS (\text{opposite } \angle T) < ST (\text{opposite } \angle R) < RT (\text{opposite } \angle S) \). So the order of sides from least to greatest is \( RS < ST < RT \). Now let's check the options:
- Option 1: \( ST < RS < RT \) – incorrect.
- Option 2: \( RT < TS < RS \) – incorrect.
- Option 3: \( SR < TS < RT \) (SR is same as RS) – so \( RS < ST < RT \), which is correct? Wait the third option is \( SR < TS < RT \) (SR = RS, TS = ST). So \( RS < ST < RT \) is the correct order of sides from least to greatest. Wait but the first option selected was \( ST < RS < RT \), which is wrong. Wait maybe I made a mistake in angle - side correspondence.
Wait let's re - calculate the angle at T: sum of angles in triangle is 180. \( \angle S = 70 \), \( \angle R = 68 \), so \( \angle T=180 - 70 - 68 = 42 \). So:
- Angle at T: 42°, side opposite is \( RS \) (since in triangle RST, side opposite angle T is RS: because angle at T is between R and S, so side opposite is RS).
- Angle at R: 68°, side opposite is \( ST \) (angle at R is between S and T, so side opposite is ST).
- Angle at S: 70°, side opposite is \( RT \) (angle at S is between R and T, so side opposite is RT).
So the length of a side is proportional to the measure of its opposite angle. So:
Since \( \angle T = 42^\circ < \angle R = 68^\circ < \angle S = 70^\circ \), then the lengths of the sides opposite these angles are in the same order. So \( RS < ST < RT \) (because \( RS \) is opposite \( \angle T \), \( ST \) is opposite \( \angle R \), \( RT \) is opposite \( \angle S \)).
Now let's check the options:
- \( ST < RS < RT \) – This would mean \( ST \) (opposite \( \angle R = 68^\circ \)) is less than \( RS \) (opposite \( \angle T = 42^\circ \)), which is false because \( 68^\circ>42^\circ \), so \( ST > RS \).
- \( RT < TS < RS \) – \( RT \) is opposite \(…
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The correct option is C. \( SR < TS < RT \) (assuming the third option is labeled as C, but in the image, the third option is \( SR < TS < RT \))