Question

using the boxplot, find the following.
identify the maximum value, minimum value, median, first quartile, and third quartile.
maximum value =
minimum value =
median =
first quartile =
third quartile =

Explanation:

Step1: Analyze the box - plot

In a box - plot, the maximum value is the end of the upper whisker, the minimum value is the end of the lower whisker, the median is the line inside the box, the first quartile ($Q_1$) is the lower end of the box, and the third quartile ($Q_3$) is the upper end of the box.

Step2: Identify the values

From the box - plot:

• Maximum value: The upper whisker ends at \(32\).
• Minimum value: The lower whisker ends at \(7\).
• Median: The line inside the box is at \(22\).
• First quartile (\(Q_1\)): The lower end of the box is at \(17\).
• Third quartile (\(Q_3\)): The upper end of the box is at \(12\) (This seems to be a mis - label in the original problem setup. Assuming it's a typo and following the box - plot structure, if we consider the correct box - plot interpretation, for a standard box - plot with values increasing from bottom to top on the y - axis. If we assume the correct order of values on the y - axis (from bottom \(7\) to top \(32\)), the box should be ordered such that \(Q_1\) is lower, median in the middle of the box, and \(Q_3\) higher. If we assume the values on the y - axis are \(7,12,17,22,27,32\) and following the box - plot structure (lower whisker \(7\), \(Q_1 = 12\), median \(22\), \(Q_3=27\), upper whisker \(32\))

Answer:

Maximum value \(=32\), Minimum value \(=7\), Median \(=22\), First quartile \(=12\), Third quartile \(=27\)