Question

use these similar triangles on the coordinate plane to determine the equation of a straight line with a slope of 5/3 that passes through the origin. \\(\bigcirc\\) \\(y=\frac{5}{3}x\\) \\(\bigcirc\\) \\(y=\frac{3}{5}x\\) \\(\bigcirc\\) \\(y = 3x + 5\\) \\(\bigcirc\\) \\(y = 5x + 3\\)

Explanation:

Step1: Recall line equation through origin

The line passes through (0,0), so its equation is $y = mx$ where $m$ is slope.

Step2: Substitute given slope

Slope $m = \frac{5}{3}$, so equation is $y = \frac{5}{3}x$.

Answer:

A. $y=\frac{5}{3}x$