Question

use the theoretical probability formula to solve the problem. express the probability as a fraction reduced to lowest terms. use the spinner below to answer the question. assume that it is equally probable that the pointer will land on any one of the five numbered spaces. if the pointer lands on a borderline, spin again. find the probability that the arrow will land on an odd number.

Explanation:

Step1: Identify total outcomes

The spinner has 5 numbered spaces, so the total number of possible outcomes is $n(S)=5$.

Step2: Identify favorable outcomes

The odd - numbered spaces are 1, 3, 5. So the number of favorable outcomes is $n(E)=3$.

Step3: Calculate probability

The theoretical probability formula is $P(E)=\frac{n(E)}{n(S)}$. Substituting the values, we get $P(E)=\frac{3}{5}$.

Answer:

B. $\frac{3}{5}$