Question

use the spinner shown. it is equally probable that the pointer will land on any one of the six regions. if the pointer lands on a borderline, spin again. if the pointer is spun twice, find the probability that it will land on grey and then blue find the probability that the spinner will land on grey and then blue. (type an integer or a simplified fraction.)

Explanation:

Step1: Determine probability of grey

There are 6 regions. Grey appears 1 time. So \( P(\text{grey}) = \frac{1}{6} \).

Step2: Determine probability of blue

Blue appears 3 times. So \( P(\text{blue}) = \frac{3}{6}=\frac{1}{2} \).

Step3: Multiply the probabilities

Since the spins are independent, \( P(\text{grey then blue}) = P(\text{grey}) \times P(\text{blue}) = \frac{1}{6} \times \frac{1}{2} = \frac{1}{12} \).

Answer:

\(\frac{1}{12}\)