Question

use the probability distribution for the random variable \\(x\\) to answer the question.

\\(\

$$\begin{array}{c|cccccc} x & 0 & 1 & 2 & 3 & 4 & 5 \\\\ \\hline p(x) & 0.35 & 0.2 & 0.17 & 0.19 & 0.03 & 0.06 \\end{array}$$

\\)

locate the interval \\(\mu \pm 2\sigma\\) on the \\(x\\)-axis of a probability histogram. you are given that the mean is 1.53 and the standard deviation is 1.49. what is the probability that \\(x\\) will fall into this interval?

Explanation:

Calculate the interval boundaries

Using the Discrete Random Variables knowledge point

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The interval is \([-1.45, 4.51]\).

Identify values of x within the interval

Using the Discrete Random Variables knowledge point

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Sum the probabilities of the identified values

Using the Discrete Random Variables knowledge point

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Answer:

Use the probability distribution for the random variable \(x\) to answer the question.

\(x\)	0	1	2	3	4	5

Locate the interval \(\mu \pm 2\sigma\) on the x-axis of a probability histogram. You are given that the mean is 1.53 and the standard deviation is 1.49. What is the probability that \(x\) will fall into this interval?
<blank>0.94</blank>