Question

use the probability distribution to complete parts (a) through (d) below.

the probability distribution of number of televisions per household in a small town
\\(\

$$\begin{array}{lcccc} x & 0 & 1 & 2 & 3 \\\\ p(x) & 0.02 & 0.16 & 0.28 & 0.54 \\end{array}$$

\\)

(a) find the probability of randomly selecting a household that has one or two televisions.

the probability is 0.44.
(type an integer or a decimal. do not round.)

(b) find the probability of randomly selecting a household that has two or more televisions.

the probability is .
(type an integer or a decimal. do not round.)

Explanation:

Calculate the probability for part (a)

$$ P(X = 1 \text{ or } X = 2) = P(1) + P(2) = 0.16 + 0.28 = 0.44 $$

Calculate the probability for part (b)

$$ P(X \ge 2) = P(2) + P(3) = 0.28 + 0.54 = 0.82 $$

Answer:

Question 1

(a) Find the probability of randomly selecting a household that has one or two televisions.

The probability is <blank>0.44</blank>.

Question 2

(b) Find the probability of randomly selecting a household that has two or more televisions.

The probability is <blank>0.82</blank>.