QUESTION IMAGE
Question
use the given statistics to complete parts (a) and (b). assume that the populations are normally distributed
(a) test whether \\( \mu _ { 1 } > \mu _ { 2 } \\) at the \\( \alpha = 0.01 \\) level of significance for the given sample data
(b) construct a \\( 99 \\% \\) confidence interval about \\( \mu _ { 1 } - \mu _ { 2 } \\)
0.52 (round to two decimal places as needed)
determine the p - value for this hypothesis test.
0.305 (round to three decimal places as needed)
state the conclusion for this hypothesis test.
a. reject \\( h _ { 0 } \\). there is not sufficient evidence at the \\( \alpha = 0.01 \\) level of significance to conclude that \\( \mu _ { 1 } > \mu _ { 2 } \\)
b. reject \\( h _ { 0 } \\). there is sufficient evidence at the \\( \alpha = 0.01 \\) level of significance to conclude that \\( \mu _ { 1 } > \mu _ { 2 } \\)
c. do not reject \\( h _ { 0 } \\). there is sufficient evidence at the \\( \alpha = 0.01 \\) level of significance to conclude that \\( \mu _ { 1 } > \mu _ { 2 } \\)
d. do not reject \\( h _ { 0 } \\). there is not sufficient evidence at the \\( \alpha = 0.01 \\) level of significance to conclude that \\( \mu _ { 1 } > \mu _ { 2 } \\)
(b) the \\( 99 \\% \\) confidence interval about \\( \mu _ { 1 } - \mu _ { 2 } \\) is the range from a lower bound of \\( \square \\) to an upper bound of \\( \square \\)
(round to three decimal places as needed.)
Step1: Calculate the degrees of freedom
For two - sample \(t\) - test, the degrees of freedom \(df=\min(n_1 - 1,n_2 - 1)\). Here \(n_1 = 26\), \(n_2=18\). So \(df=\min(26 - 1,18 - 1)=17\)
Step2: Determine the critical value for confidence interval
For a \(99\%\) confidence interval and \(df = 17\), the critical value \(t_{\alpha/2}\) (where \(\alpha=1 - 0.99 = 0.01\), \(\alpha/2=0.005\)) from the \(t\) - distribution table is \(t_{0.005,17}=2.898\)
Step3: Calculate the standard error
The formula for the standard error \(SE=\sqrt{\frac{s_1^{2}}{n_1}+\frac{s_2^{2}}{n_2}}\), where \(s_1 = 4.0\), \(n_1 = 26\), \(s_2=9.8\), \(n_2 = 18\)
Step4: Calculate the lower and upper bounds of the confidence interval
The point estimate is \(\bar{x}_1-\bar{x}_2=45.7 - 44.4 = 1.3\)
The lower bound \(LB=(\bar{x}_1-\bar{x}_2)-t_{\alpha/2}\times SE\)
The upper bound \(UB=(\bar{x}_1-\bar{x}_2)+t_{\alpha/2}\times SE\)
Snap & solve any problem in the app
Get step-by-step solutions on Sovi AI
Photo-based solutions with guided steps
Explore more problems and detailed explanations
The \(99\%\) confidence interval about \(\mu_1-\mu_2\) is the range from a lower bound of \(-5.771\) to an upper bound of \(8.371\)