Question

use the accompanying table of z - scores and percentiles to find the percentage of data items in a normal distribution that lie a. below and b. above a z - score of - 0.55
click the icon to view the table of z - scores and percentiles

a. the percentage of data items that lie below the z - score is 29.12%.
(round to two decimal places as needed.)
b. the percentage of data items that lie above the z - score is \\( \square \\% \\).
(round to two decimal places as needed.)

Explanation:

Step1: Recall the total percentage

The total percentage of data in a normal distribution is \(100\%\).

Step2: Calculate the percentage above the \(z -\)score

We know the percentage of data items below \(z=- 0.55\) is \(29.12\%\). To find the percentage of data items above \(z =-0.55\), we use the formula \(P(\text{above})=100\% - P(\text{below})\).
Substitute \(P(\text{below}) = 29.12\%\) into the formula: \(P(\text{above})=100 - 29.12\)

$$P(\text{above})=70.88$$

Answer:

\(70.88\)