Question

unit 7 review assignment

1. $3x^3 - 4x^2 - 12x + 16$

Explanation:

Step1: Group terms

Group the first two terms and the last two terms: $(3x^3 - 4x^2) + (-12x + 16)$

Step2: Factor out GCF from each group

Factor out $x^2$ from the first group and $-4$ from the second group: $x^2(3x - 4) - 4(3x - 4)$

Step3: Factor out common binomial

Factor out $(3x - 4)$: $(3x - 4)(x^2 - 4)$

Step4: Factor difference of squares

Factor $x^2 - 4$ as a difference of squares: $(3x - 4)(x - 2)(x + 2)$

Answer:

$(3x - 4)(x - 2)(x + 2)$