Question

unilateral tolerance
these exercises require computation with unilateral tolerance clearance fits between mating parts. given dimensions a and b, compute the missing values in the tables.
refer to figure 7 - 19 to determine the missing values in figure 7 - 20.
dia a $pm$ 0.0000\ 0.0014\
dia b $pm$ 0.0014\ 0.0000\
figure 7 - 19

	basic dimension (in.)	maximum diameter (in.)	minimum diameter (in.)	maximum clearance (in.)	minimum clearance (in.)
dia b	1.7136
56. dia a	0.2962
dia b	0.2970
57. dia a	2.8064
dia b	2.8075

figure 7 - 20

Explanation:

Step1: Calculate maximum diameter of DIA A

For DIA A with tolerance $\pm0.0000, - 0.0014$, the maximum diameter is the basic dimension, since the upper - tolerance is 0. For the first row where basic dimension of DIA A is 1.7120, the maximum diameter of DIA A is 1.7120. For the second row with basic dimension 0.2962, the maximum diameter of DIA A is 0.2962. For the third row with basic dimension 2.8064, the maximum diameter of DIA A is 2.8064.

Step2: Calculate minimum diameter of DIA A

The minimum diameter of DIA A is the basic dimension minus the lower - tolerance value. For the first row: $1.7120−0.0014 = 1.7106$. For the second row: $0.2962−0.0014 = 0.2948$. For the third row: $2.8064−0.0014 = 2.8050$.

Step3: Calculate maximum diameter of DIA B

For DIA B with tolerance $+0.0014, - 0.0000$, the maximum diameter is the basic dimension plus the upper - tolerance value. For the first row: $1.7136 + 0.0014=1.7150$. For the second row: $0.2970 + 0.0014 = 0.2984$. For the third row: $2.8075+0.0014 = 2.8089$.

Step4: Calculate minimum diameter of DIA B

The minimum diameter of DIA B is the basic dimension, since the lower - tolerance is 0. For the first row, it is 1.7136. For the second row, it is 0.2970. For the third row, it is 2.8075.

Step5: Calculate maximum clearance

The maximum clearance is the difference between the maximum diameter of DIA B and the minimum diameter of DIA A. For the first row: $1.7150−1.7106 = 0.0044$. For the second row: $0.2984−0.2948 = 0.0036$. For the third row: $2.8089−2.8050 = 0.0039$.

Step6: Calculate minimum clearance

The minimum clearance is the difference between the minimum diameter of DIA B and the maximum diameter of DIA A. For the first row: $1.7136−1.7120 = 0.0016$. For the second row: $0.2970−0.2962 = 0.0008$. For the third row: $2.8075−2.8064 = 0.0011$.

Basic Dimension (in.)	Maximum Diameter (in.)	Minimum Diameter (in.)	Maximum Clearance (in.)	Minimum Clearance (in.)
DIA B (1.7136)	1.7150	1.7136	0.0044	0.0016
DIA A (0.2962)	0.2962	0.2948	0.0036	0.0008
DIA B (0.2970)	0.2984	0.2970	0.0036	0.0008
DIA A (2.8064)	2.8064	2.8050	0.0039	0.0011
DIA B (2.8075)	2.8089	2.8075	0.0039	0.0011

Answer:

Basic Dimension (in.)	Maximum Diameter (in.)	Minimum Diameter (in.)	Maximum Clearance (in.)	Minimum Clearance (in.)
DIA B (1.7136)	1.7150	1.7136	0.0044	0.0016
DIA A (0.2962)	0.2962	0.2948	0.0036	0.0008
DIA B (0.2970)	0.2984	0.2970	0.0036	0.0008
DIA A (2.8064)	2.8064	2.8050	0.0039	0.0011
DIA B (2.8075)	2.8089	2.8075	0.0039	0.0011