Question

type the correct answer in the box. use numerals instead of words. if necessary, use / for the fraction bar.
what value of p makes the equation true?
$-3p + \frac{1}{8} = -\frac{1}{4}$
$p = \square$

Explanation:

Step1: Subtract \( \frac{1}{8} \) from both sides

To isolate the term with \( p \), we subtract \( \frac{1}{8} \) from both sides of the equation \( -3p + \frac{1}{8} = -\frac{1}{4} \). This gives us \( -3p = -\frac{1}{4} - \frac{1}{8} \).

Step2: Find a common denominator and simplify

The common denominator of 4 and 8 is 8. So, \( -\frac{1}{4} = -\frac{2}{8} \). Then, \( -\frac{2}{8} - \frac{1}{8} = -\frac{3}{8} \). Now our equation is \( -3p = -\frac{3}{8} \).

Step3: Divide both sides by -3

To solve for \( p \), we divide both sides of the equation \( -3p = -\frac{3}{8} \) by -3. Dividing by -3 is the same as multiplying by \( -\frac{1}{3} \). So, \( p = (-\frac{3}{8}) \times (-\frac{1}{3}) \). The negatives cancel out, and the 3s cancel out, leaving \( p = \frac{1}{8} \).

Answer:

\( \frac{1}{8} \)