Question

type the correct answer in the box. express your answer to three significant figures.
the gas inside a large engine cylinder initially has a pressure of 105 kilopascals and a volume of 2.031 liters. if the gas is compressed at constant temperature to a volume of 0.356 liter, what is its new pressure?
the pressure of the compressed gas is kilopascal

Explanation:

Step1: Identify the law

Boyle's law: $P_1V_1 = P_2V_2$.

Step2: Define the variables

$P_1 = 105$ kPa, $V_1=2.031$ L, $V_2 = 0.356$ L, $P_2$ is unknown.

Step3: Rearrange the formula for $P_2$

$P_2=\frac{P_1V_1}{V_2}$.

Step4: Substitute the values

$P_2=\frac{105\times2.031}{0.356}$.
$P_2=\frac{213.255}{0.356}\approx601.84$.

Step5: Round to three - significant figures

$P_2 = 601$ kPa.

Answer:

601