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Question
the two triangles are similar. solve for de.
Step1: Set up proportion
Since the triangles are similar, \(\frac{AB}{BC}=\frac{DE}{EF}\). Substitute \(AB = 14\), \(BC = 8\), \(EF = 6\). So \(\frac{14}{8}=\frac{DE}{6}\).
Step2: Solve for \(DE\)
Cross - multiply: \(8\times DE=14\times6\). Then \(8DE = 84\). Divide both sides by \(8\): \(DE=\frac{84}{8}=\frac{21}{2}=10.5\).
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\(10.5\)