Question

two teams are playing tug of war. team a pulls to the right with a force of 450 n. team b pulls to the left with a force of 415 n. what is the net force on the rope, and what is its direction? 35 n to the right 35 n to the left 865 n to the right 865 n to the left

Explanation:

Step1: Define forces' directions

Let right - direction force be positive and left - direction force be negative. Team A's force \(F_A = + 450\space N\) (pulls to the right), Team B's force \(F_B=- 415\space N\) (pulls to the left).

Step2: Calculate net force

The net force \(F_{net}=F_A + F_B\). Substitute the values: \(F_{net}=450+( - 415)=450 - 415 = 35\space N\). Since the result is positive, the direction of the net force is to the right.

Answer:

35 N to the right