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Question
- two rectangles are similar. one has a length of 14 cm and a width of 9 cm, and the other has a width of 3 cm. find the length of the second rectangle. round to the nearest tenth if necessary 1.9 cm 4.7 cm 3.5 cm 5.4 cm
Step1: Set up proportion
Since the rectangles are similar, the ratios of their corresponding sides are equal. Let the length of the second rectangle be \(x\). Then \(\frac{14}{9}=\frac{x}{3}\).
Step2: Solve for \(x\)
Cross - multiply: \(9x = 14\times3\), so \(9x=42\). Then \(x=\frac{42}{9}=\frac{14}{3}\approx4.7\).
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\(4.7\mathrm{cm}\)