Question

two pet stores offer customers the opportunity to donate money, in dollar increments, to the local humane society at the register. the dot plots below show the amounts donated last week.
pet store 1
pet store 2
2 3 4 5 6 7
amount donated ($)
1 2 3 4 5 6
amount donated ($)
the variability at each pet store is 1.4. the difference between the mode amount donated at each pet store is approximately how many times the variability?
a. 4
b. 5
c. 3
d. 2

Explanation:

Step1: Find the mode of each pet store

For Pet Store 1 (blue dots), the mode is the amount with the most dots. Looking at the dot plot, 6 has the most dots, so mode of Pet Store 1 is 6.
For Pet Store 2 (red dots), the mode is the amount with the most dots. Looking at the dot plot, 3 has the most dots, so mode of Pet Store 2 is 3.

Step2: Calculate the difference between the modes

Difference = \( 6 - 3 = 3 \)

Step3: Find how many times the variability (1.4) fits into the difference

Number of times = \( \frac{3}{1.4} \approx 2.14 \), which is approximately 2. Wait, wait, no—wait, maybe I made a mistake. Wait, let's recheck the modes. Wait Pet Store 1: looking at the blue dots, at 6, how many? Let's count: 2 has 2, 3 has 4, 4 has 2, 5 has 3, 6 has 5, 7 has 3? Wait no, maybe I miscounted. Wait the dot plot for Pet Store 1: 2: 2 dots, 3: 4 dots, 4: 2 dots, 5: 3 dots, 6: 5 dots, 7: 3 dots? Wait no, maybe the mode is 6? Wait Pet Store 2: 1: 4 dots, 2: 3 dots, 3: 5 dots, 4: 2 dots, 5: 3 dots, 6: 2 dots. So mode of Pet Store 2 is 3 (5 dots). Pet Store 1: 6 has 5 dots? Wait 3 has 4, 6 has 5? Wait maybe I miscounted. Wait the blue dots: 2: two, 3: four, 4: two, 5: three, 6: five, 7: three. So mode is 6 (5 dots). Pet Store 2: red dots: 1: four, 2: three, 3: five, 4: two, 5: three, 6: two. So mode is 3 (5 dots). Then difference is 6 - 3 = 3. Variability is 1.4. So 3 / 1.4 ≈ 2.14, which is approximately 2? But wait, maybe I messed up the modes. Wait another way: maybe Pet Store 1's mode is 3? No, 3 has 4, 6 has 5. Wait 6 has more. So 6-3=3. 3 /1.4 ≈2.14, which is ~2. But the options are 4,5,3,2. Wait maybe I made a mistake in modes. Wait let's check again. Pet Store 1: 2: 2, 3: 4, 4: 2, 5: 3, 6: 5, 7: 3. So 6 is mode (5 dots). Pet Store 2: 1: 4, 2: 3, 3: 5, 4: 2, 5: 3, 6: 2. So 3 is mode (5 dots). Difference 3. 3 /1.4 ≈2.14, so approximately 2. But option D is 2. Wait but maybe I miscounted the modes. Wait maybe Pet Store 1's mode is 3? No, 3 has 4, 6 has 5. So 6 is higher. So difference 3. 3/1.4≈2. So answer is D? Wait but let's check again. Wait the problem says "the difference between the mode amount donated at each pet store is approximately how many times the variability?" Variability is 1.4. So 3 /1.4 ≈2. So the answer is D. 2.

Answer:

D. 2