Question

two people push a 2610 kg car that is initially at rest, both in the same direction. one person pushes with a force of 97.2 n. the car accelerates at 0.520 m/s^{2}.
how much force does the other person exert onto the car?
f = ? n
do not account for friction.

Explanation:

⚡ Using what you learned: newton's laws of motion

Step 1: Calculate the net force

$$ F_{\text{net}} = m \cdot a $$

$$ F_{\text{net}} = 2610 \text{ kg} \cdot 0.520 \text{ m/s}^2 = 1357.2 \text{ N} $$

Step 2: Find the force of the second person

$$ F_{\text{net}} = F_1 + F_2 $$

$$ 1357.2 \text{ N} = 97.2 \text{ N} + F_2 $$

$$ F_2 = 1357.2 \text{ N} - 97.2 \text{ N} = 1260 \text{ N} $$

Answer:

1260