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5. two parents think their baby was switched at the hospital. its 1968 …

Question

  1. two parents think their baby was switched at the hospital. its 1968 so dna fingerprinting technology does not exist yet. the mother has blood type “o,” the father has blood type “ab,” and the baby has blood type “b.”

a. mother’s genotype: ______
b. father’s genotype: ______
c. baby’s genotype: ____ or ____
d. punnett square showing all possible genotypes for children produced by this couple.
e. was the baby switched?

  1. two other parents think their baby was switched at the hospital. the mother has blood type “a,” the father has blood type “b,” and the baby has blood type “ab.”

a. mother’s genotype: ____ or ____
b. father’s genotype: ____ or ____
c. baby’s genotype: ______
d. punnett square that shows the baby’s genotype as a possibility.
e. was the baby switched?

  1. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.
nameblood type
babytype b
the postmantype o
the ups drivertype ab
the waitertype a
the cable guytype b
  1. based on the information in this table, which man could not be the father of the baby? justify your answer with a punnett square.
nameblood type
babytype a
pharmacisttype o
hairdressertype ab
cabdrivertype a
flight attendanttype b
  1. explain why blood type data cannot prove who the father of a baby is, and can only prove who the father is not.

Explanation:

was not switched. The mother (Type A, e.g., \( I^A i \)) and father (Type B, e.g., \( I^B i \)) can produce a baby with Type AB (genotype \( I^A I^B \)) via a Punnett square (e.g., mother donates \( I^A \), father donates \( I^B \)).

Question 7
Brief Explanations
  • Mother’s blood type: A (genotype \( I^A \_ \))
  • Baby’s blood type: B (genotype \( I^B i \) or \( I^B I^B \))

Mother (A) can only donate \( I^A \) or \( i \) (if genotype \( I^A i \)). For the baby to have Type B, it needs a \( I^B \) allele (from the father) and either \( I^B \) or \( i \) (from the mother, but mother is A, so cannot donate \( I^B \)).

  • If mother is \( I^A I^A \): Donates \( I^A \) → baby would have \( I^A \) (so blood type A or AB, not B).
  • If mother is \( I^A i \): Donates \( i \) → baby would need \( I^B \) from father, but baby’s blood type is B (so genotype \( I^B i \)). Wait, but mother is A (can’t donate \( I^B \)), so baby’s \( I^B \) must come from father. But let’s check the table:

Table for Q7:

NameBlood Type
BabyType B
The PostmanType O
The UPS driverType AB
The waiterType A
The cable guyType B

Possible fathers: Postman (O, \( ii \)), UPS driver (AB, \( I^A I^B \)), waiter (A, \( I^A \_ \)), cable guy (B, \( I^B \_ \)).

  • Mother (A, \( I^A i \)) × Postman (O, \( ii \)):

Punnett square:

\( i \)\( i \)
\( i \)\( ii \) (O)\( ii \) (O)

→ Baby can only be A or O (not B) → Postman is ruled out.

  • Mother (A, \( I^A i \)) × UPS driver (AB, \( I^A I^B \)):

Punnett square:

\( I^A \)\( I^B \)
\( i \)\( I^A i \) (A)\( I^B i \) (B)

→ Baby can be B (genotype \( I^B i \)) → UPS driver is a possible father.

  • Mother (A, \( I^A i \)) × Waiter (A, \( I^A i \)):

Punnett square:

\( I^A \)\( i \)
\( i \)\( I^A i \) (A)\( ii \) (O)

→ Baby can only be A or O (not B) → Waiter is ruled out.

  • Mother (A, \( I^A i \)) × Cable guy (B, \( I^B i \)):

Punnett square:

\( I^B \)\( i \)
\( i \)\( I^B i \) (B)\( ii \) (O)

→ Baby can be B (genotype \( I^B i \)) → Cable guy is a possible father.

But the question is “Was the baby switched?” Wait, no—wait, the mother is Type A, baby is Type B. Mother (A) can’t donate \( I^B \), so baby’s \( I^B \) must come from father. But if the father is, say, the cable guy (Type B, \( I^B i \)), then baby can be B ( \( I^B i \) ). But wait, the table: Mother is A, baby is B. Let’s check the possible fathers:

  • Postman (O): Can’t give \( I^B \) (only \( i \)) → baby can’t be B.
  • UPS driver (AB): Can give \( I^B \) → baby could be B ( \( I^B i \) if mother is \( I^A i \) ).
  • Waiter (A): Can’t give \( I^B \) → baby can’t be B.
  • Cable guy (B): Can give \( I^B \) → baby could be B.

But the question is “Was the baby switched?” Wait, no—wait, the mother is A, baby is B. If the mother is \( I^A i \), and father is, say, cable guy ( \( I^B i \) ), then baby can be B. But maybe the intended father is not possible. Wait, let's re-express:

Mother (A) genotype: \( I^A i \) (to donate \( i \))
Baby (B) genotype: \( I^B i \) (needs \( I^B \) from father, \( i \) from mother)

So possible fathers: UPS driver (AB,

Answer:

  • Mother’s blood type: A (genotype \( I^A \_ \))
  • Baby’s blood type: B (genotype \( I^B i \) or \( I^B I^B \))

Mother (A) can only donate \( I^A \) or \( i \) (if genotype \( I^A i \)). For the baby to have Type B, it needs a \( I^B \) allele (from the father) and either \( I^B \) or \( i \) (from the mother, but mother is A, so cannot donate \( I^B \)).

  • If mother is \( I^A I^A \): Donates \( I^A \) → baby would have \( I^A \) (so blood type A or AB, not B).
  • If mother is \( I^A i \): Donates \( i \) → baby would need \( I^B \) from father, but baby’s blood type is B (so genotype \( I^B i \)). Wait, but mother is A (can’t donate \( I^B \)), so baby’s \( I^B \) must come from father. But let’s check the table:

Table for Q7:

NameBlood Type
BabyType B
The PostmanType O
The UPS driverType AB
The waiterType A
The cable guyType B

Possible fathers: Postman (O, \( ii \)), UPS driver (AB, \( I^A I^B \)), waiter (A, \( I^A \_ \)), cable guy (B, \( I^B \_ \)).

  • Mother (A, \( I^A i \)) × Postman (O, \( ii \)):

Punnett square:

\( i \)\( i \)
\( i \)\( ii \) (O)\( ii \) (O)

→ Baby can only be A or O (not B) → Postman is ruled out.

  • Mother (A, \( I^A i \)) × UPS driver (AB, \( I^A I^B \)):

Punnett square:

\( I^A \)\( I^B \)
\( i \)\( I^A i \) (A)\( I^B i \) (B)

→ Baby can be B (genotype \( I^B i \)) → UPS driver is a possible father.

  • Mother (A, \( I^A i \)) × Waiter (A, \( I^A i \)):

Punnett square:

\( I^A \)\( i \)
\( i \)\( I^A i \) (A)\( ii \) (O)

→ Baby can only be A or O (not B) → Waiter is ruled out.

  • Mother (A, \( I^A i \)) × Cable guy (B, \( I^B i \)):

Punnett square:

\( I^B \)\( i \)
\( i \)\( I^B i \) (B)\( ii \) (O)

→ Baby can be B (genotype \( I^B i \)) → Cable guy is a possible father.

But the question is “Was the baby switched?” Wait, no—wait, the mother is Type A, baby is Type B. Mother (A) can’t donate \( I^B \), so baby’s \( I^B \) must come from father. But if the father is, say, the cable guy (Type B, \( I^B i \)), then baby can be B ( \( I^B i \) ). But wait, the table: Mother is A, baby is B. Let’s check the possible fathers:

  • Postman (O): Can’t give \( I^B \) (only \( i \)) → baby can’t be B.
  • UPS driver (AB): Can give \( I^B \) → baby could be B ( \( I^B i \) if mother is \( I^A i \) ).
  • Waiter (A): Can’t give \( I^B \) → baby can’t be B.
  • Cable guy (B): Can give \( I^B \) → baby could be B.

But the question is “Was the baby switched?” Wait, no—wait, the mother is A, baby is B. If the mother is \( I^A i \), and father is, say, cable guy ( \( I^B i \) ), then baby can be B. But maybe the intended father is not possible. Wait, let's re-express:

Mother (A) genotype: \( I^A i \) (to donate \( i \))
Baby (B) genotype: \( I^B i \) (needs \( I^B \) from father, \( i \) from mother)

So possible fathers: UPS driver (AB,