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Question
the two isosceles triangles are similar, what is the length of the base of the smaller triangle? 14 6 2.6 3.8 6 14
Step1: Set up proportion
Since the triangles are similar, the ratio of corresponding sides is equal. Let the base of the smaller triangle be \(x\). The ratio of the sides is \(\frac{6}{14}=\frac{x}{6}\).
Step2: Solve for \(x\)
Cross - multiply: \(14x = 6\times6\), so \(14x=36\), then \(x=\frac{36}{14}\approx2.6\).
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\(2.6\)