Question

1. two charges that each have a magnitude of 0.03 c are 10m away from each other. what is the force between them?

Explanation:

Step1: Identify the formula

Coulomb's law: \(F = k\frac{q_1q_2}{r^2}\), where \(k = 9\times10^{9}\space N\cdot m^{2}/C^{2}\), \(q_1 = q_2=0.03\space C\), \(r = 10\space m\)

Step2: Substitute the values into the formula

\(F=(9\times 10^{9})\frac{(0.03)(0.03)}{10^{2}}\)
First calculate \((0.03)(0.03)=9\times10^{-4}\)
Then \(\frac{9\times10^{-4}}{10^{2}} = 9\times10^{-6}\)
Finally \(F=(9\times 10^{9})(9\times10^{-6})\)
\(F = 81\times10^{3}=8.1\times 10^{4}\space N\)

Answer:

\(8.1\times 10^{4}\space N\)