Question

1. triangle wxy find side lengths first! c = \sqrt{a^{2}+b^{2}} (-3,-4)=w a = 5 = wy (-3,-9)=y b = 7 = yx (4,-9)=x 8.6 = wx wx = c = \sqrt{5^{2}+7^{2}} = 8.6 add 5 + 7+8.6 = perimeter = 20.6 sides up \frac{1}{2}6\cdot h area = \frac{35}{2}

Explanation:

Step1: Identify side - lengths

Let \(WY = 5\), \(YX=7\). For side \(WX\), use the Pythagorean theorem \(c=\sqrt{a^{2}+b^{2}}\) where \(a = 5\) and \(b = 7\). So \(WX=\sqrt{5^{2}+7^{2}}=\sqrt{25 + 49}=\sqrt{74}\approx8.6\).

Step2: Calculate perimeter

Perimeter \(P=WY + YX+WX\). Substitute the values: \(P = 5+7 + 8.6=20.6\).

Step3: Calculate area

Assume base \(b = 7\) and height \(h = 5\). Area \(A=\frac{1}{2}\times b\times h=\frac{1}{2}\times7\times5=\frac{35}{2}\).

Answer:

Perimeter: \(20.6\)
Area: \(\frac{35}{2}\)