Question

triangle pqr has vertices p( - 2,6), q( - 8,4), and r(1, - 2). it is translated according to the rule (x,y)→(x - 2,y - 16).
what is the y - value of p?

• 18
• 16
• 12
• 10

Explanation:

Step1: Identify the y - coordinate of point P

The coordinates of point \( P\) are \((-2,6)\). The \(y\) - coordinate of point \(P\) is \(y = 6\).

Step2: Apply the translation rule to the y - coordinate

The translation rule is \((x,y)\to(x - 2,y-16)\). For the \(y\) - coordinate, we substitute \(y = 6\) into \(y-16\).

$$y'=6 - 16$$

$$y'=- 10$$

Answer:

\(-10\)