Question

triangle pqr has vertices ( p(-2,6) ), ( q(-8,4) ), and ( r(1,-2) ). it is translated according to the rule ( (x,y)\to(x - 2,y - 16) ).
what is the ( y )-value of ( p )?
-18
-16
-12
-10

Explanation:

Step1: Identify the y - coordinate of point P

The coordinates of point \( P\) are \((-2,6)\), so the \(y\) - coordinate of \(P\) is \(y = 6\).

Step2: Apply the translation rule to the y - coordinate

The translation rule is \((x,y)\to(x - 2,y-16)\). For the \(y\) - coordinate, we substitute \(y = 6\) into \(y-16\).
We get \(y'=6 - 16\).

Step3: Calculate the value of \(y'\)

\(y'=6-16=-10\).

Answer:

-10