Question

1. triangle mnp with vertices m(-7,6),n(-1,2), and p(-6,0): 270° clockwise m (__,) n (,) p (,__)

Explanation:

Step1: Recall the rotation rule

When rotating a point \((x,y)\) \(270^{\circ}\) clockwise about the origin, the rule is \((x,y)\to(y, -x)\).

Step2: Apply the rule to point \(M(-7,6)\)

For \(M(-7,6)\), using the rule \((x,y)\to(y, -x)\), we substitute \(x = - 7\) and \(y = 6\). So \(M'=(6,7)\).

Step3: Apply the rule to point \(N(-1,2)\)

For \(N(-1,2)\), substitute \(x=-1\) and \(y = 2\) into the rule \((x,y)\to(y, -x)\). Then \(N'=(2,1)\).

Step4: Apply the rule to point \(P(-6,0)\)

For \(P(-6,0)\), substitute \(x=-6\) and \(y = 0\) into the rule \((x,y)\to(y, -x)\). So \(P'=(0,6)\).

Answer:

\(M'(6,7)\), \(N'(2,1)\), \(P'(0,6)\)