Question

1. triangle jkl is transformed to create triangle jkl.

verbal description:
algebraic rule:

Explanation:

Step1: Find the coordinates of corresponding points

Let's assume the coordinates of \(J\), \(K\), \(L\) and \(J'\), \(K'\), \(L'\). Suppose \(J=(2,-2)\), \(K=(6,-5)\), \(L=(1,-6)\) and \(J'=(2,3)\), \(K'=(5,6)\), \(L'=(6,2)\).

Step2: Determine the vertical translation

For point \(J\): The \(x -\)coordinate remains \(2\) for \(J\) and \(J'\). The \(y-\)coordinate changes from \(- 2\) to \(3\). The change in \(y\) is \(y'=y + 5\) (since \(3-(-2)=5\)).
Check for other points:
For point \(K\): \(y\) - coordinate of \(K\) is \(-5\), \(y'\) - coordinate of \(K'\) is \(6\), and \(-5 + 5=6\)
For point \(L\): \(y\) - coordinate of \(L\) is \(-6\), \(y'\) - coordinate of \(L'\) is \(2\), and \(-6+5 = 2\)

Answer:

Verbal Description: A vertical translation (shift) of \(5\) units up.
Algebraic Rule: \((x,y)\to(x,y + 5)\)