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QUESTION IMAGE

triangle abc was transformed to create triangle def. which statement is…

Question

triangle abc was transformed to create triangle def. which statement is true regarding the side in the image that corresponds to \\(\overline{ba}\\)? \\(\overline{bc}\\) corresponds to \\(\overline{ba}\\) because they are about the same length. \\(\overline{ed}\\) corresponds to \\(\overline{ba}\\) because they are in the same position. \\(\overline{ef}\\) corresponds to \\(\overline{ba}\\) because the transformation is isometric. \\(\overline{fd}\\) corresponds to \\(\overline{ba}\\) because the length is not preserved.

Explanation:

Step1: Understand isometric transformation

Isometric transformation (like translation, rotation, reflection) preserves the shape and size of the figure. So corresponding sides are equal in length.

Step2: Analyze each option

  • Option 1: \( \overline{BC}\) and \( \overline{BA}\) are sides of the same triangle \(ABC\), not corresponding sides of transformed triangles.
  • Option 2: \( \overline{ED}\) is not in the same relative position as \( \overline{BA}\) (consider vertex - to - vertex correspondence in isometric transformation).
  • Option 3: Since the transformation is isometric (preserves length), and in triangle \(ABC\) and \(DEF\), if we assume the transformation maps \(A\) to \(D\), \(B\) to \(E\), \(C\) to \(F\) (by the nature of isometric transformation of triangles), then \( \overline{BA}\) corresponds to \( \overline{ED}\) (wrong) or if we consider the correct vertex correspondence for side - to - side, \( \overline{BA}\) and \( \overline{EF}\) (assuming \(A\to F\), \(B\to E\), \(C\to D\) based on the shape of the triangles in isometric transformation). The length is preserved as it's isometric.
  • Option 4: Isometric transformation preserves length, so this option is wrong.

Answer:

\(\overline{EF}\) corresponds to \(\overline{BA}\) because the transformation is isometric. So the correct option is “\(\overline{EF}\) corresponds to \(\overline{BA}\) because the transformation is isometric”