Question

4 a train moving at a velocity of 15.0 m/s is accelerated to 50.0 m/s over a 12.0 second period.
what is its acceleration?

1. identify the numbers in the

problem and what you are
looking for.

1. highlight the formula you

will use to solve the problem.

1. plug the numbers into the

formula with the correct unit
in its proper location.

1. solve for the missing

variable.

1. round and circle your

answer.

1. a plane starting from rest is accelerated to its takeoff velocity of 285 km/hr during a 29.23

second period. what is its acceleration?

1. identify the numbers in the

problem and what you are
looking for.

1. highlight the formula you

will use to solve the problem.

1. plug the numbers into the

formula with the correct unit
in its proper location.

1. solve for the missing

variable.

1. round and circle your

answer.

Explanation:

Step1: Identify the values

The formula for acceleration is \(a=\frac{v_{f}-v_{i}}{t}\). Here, \(v_{i} = 0\ m/s\) (starts from rest), \(v_{f}=285\ km/hr\). Convert \(v_{f}\) to \(m/s\): \(285\times\frac{1000}{3600}=79.17\ m/s\), \(t = 29.23\ s\).

Step2: Plug into the formula

Substitute the values into \(a=\frac{v_{f}-v_{i}}{t}\), so \(a=\frac{79.17 - 0}{29.23}\).

Step3: Calculate

\(a=\frac{79.17}{29.23}\approx2.71\ m/s^{2}\).

Answer:

\(a\approx2.71\ m/s^{2}\)