Question

a tractor pulls a sled 20.0 m across a field using a constant force of 1,500 n. how much work is done by the tractor?

Explanation:

Step1: Recall the work formula

The formula for work \(W\) is \(W = F\times d\), where \(F\) is the force and \(d\) is the displacement.

Step2: Substitute the given values

Given \(F = 1500\space N\) and \(d=20.0\space m\). Then \(W=1500\times20\).

Step3: Calculate the work

\(W = 1500\times20=30000\space J\)

Answer:

30,000 J