QUESTION IMAGE
Question
5.
topic 2 systems of linear equations
number of flower wreaths
wreaths: x; income (dollars): 37x; production cost (dollars): 12x + 500; profit (dollars): 25x - 500
wreaths: 0; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
wreaths: 10; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
wreaths: 12; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
wreaths: 14; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
wreaths: 20; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
wreaths: 100; income (dollars): blank; production cost (dollars): blank; profit (dollars): blank
the productions cost and the income are equivalent when there are select flower wreaths produced.
Step1: Calculate Income for each x
Substitute each x into $37x$:
- $x=0$: $37(0)=0$
- $x=10$: $37(10)=370$
- $x=12$: $37(12)=444$
- $x=14$: $37(14)=518$
- $x=20$: $37(20)=740$
- $x=100$: $37(100)=3700$
Step2: Calculate Production Cost for each x
Substitute each x into $12x+500$:
- $x=0$: $12(0)+500=500$
- $x=10$: $12(10)+500=620$
- $x=12$: $12(12)+500=644$
- $x=14$: $12(14)+500=668$
- $x=20$: $12(20)+500=740$
- $x=100$: $12(100)+500=1700$
Step3: Calculate Profit for each x
Substitute each x into $25x-500$:
- $x=0$: $25(0)-500=-500$
- $x=10$: $25(10)-500=-250$
- $x=12$: $25(12)-500=-200$
- $x=14$: $25(14)-500=-150$
- $x=20$: $25(20)-500=0$
- $x=100$: $25(100)-500=2000$
Step4: Find break-even (income=cost)
Set $37x=12x+500$, solve for x:
$37x-12x=500$
$25x=500$
$x=\frac{500}{25}=20$
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Completed Table:
| Number of Flower Wreaths | Income (dollars) | Production Cost (dollars) | Profit (dollars) |
|---|---|---|---|
| 10 | 370 | 620 | -250 |
| 12 | 444 | 644 | -200 |
| 14 | 518 | 668 | -150 |
| 20 | 740 | 740 | 0 |
| 100 | 3700 | 1700 | 2000 |
The production cost and income are equivalent when there are 20 flower wreaths produced.