Question

timothy and ralph counted the coins in their coin collections. timothy discovered that he had 553 more coins than ralph. whose collection is worth more? how much more? answer 7–10. click the icon to view a table of the coins in the collections. d. you need to multiply the total number of coins in both collections by the value of each collection. 9. write and solve an equation to represent the total value of the coins in tim equation to represent the total value of the coins in ralphs collection. let t be the total value of timothys collection. complete the equation and so t = (919 × $0.01) + (110 × $0.05) + (□ × $0.10) + (□ × $0.25) = $27.94 (type whole numbers or decimals.) coins in the collections | type of coin | number saved timothy | ralph --- | --- | --- | --- penny image | 919 | 465 nickel image | 110 | 39 dime image | 35 | 20 quarter image | 39 | 26

Explanation:

Step1: Identify the number of dimes for Timothy

From the table, the number of dimes (10 - cent coins) Timothy has is 35. So the first blank (for dimes) is 35.

Step2: Identify the number of quarters for Timothy

From the table, the number of quarters (25 - cent coins) Timothy has is 39. So the second blank (for quarters) is 39.

Step3: Verify the calculation

Now, calculate the total value:

• Pennies: \(919\times0.01 = 9.19\)
• Nickels: \(110\times0.05 = 5.5\)
• Dimes: \(35\times0.10 = 3.5\)
• Quarters: \(39\times0.25 = 9.75\)

Sum these up: \(9.19 + 5.5 + 3.5 + 9.75 = 27.94\), which matches the given total.

Answer:

The first blank (for dimes) is 35, the second blank (for quarters) is 39, and the total value \(t = \$27.94\). So the completed equation is \(t=(919\times\$0.01)+(110\times\$0.05)+(35\times\$0.10)+(39\times\$0.25)=\$27.94\)