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Question
if three of the interior angles of a convex quadrilateral measure 93°, 140°, and 79°, find the measure of the fourth interior angle. degrees question 8 1 pts calculate the measure of each exterior angle of a regular 30 - gon. degrees
Step1: Find the sum of interior angles of a quadrilateral
The sum of interior angles of a quadrilateral is \((4 - 2)\times180^{\circ}=360^{\circ}\)
Step2: Calculate the fourth interior angle
Let the fourth interior angle be \(x\). Then \(x=360-(93 + 140+79)\)
\(x = 360 - 312\)
\(x = 48^{\circ}\)
Step3: Recall the formula for the measure of an exterior angle of a regular polygon
The sum of exterior angles of any polygon is \(360^{\circ}\). For a regular \(n -\)gon, the measure of each exterior angle \(E=\frac{360^{\circ}}{n}\)
Step4: Calculate the measure of each exterior angle of a regular 30 - gon
Here \(n = 30\), so \(E=\frac{360}{30}=12^{\circ}\)
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