Question

there are two boxes containing only blue and orange pens. box a has 9 blue pens and 6 orange pens. box b has 8 blue pens and 2 orange pens. a pen is randomly chosen from each box. list these events from least likely to most likely. event 1: choosing a blue or orange pen from box a. event 2: choosing a green pen from box b. event 3: choosing a blue pen from box b. event 4: choosing a blue pen from box a.

Explanation:

Step1: Calculate probability of Event 1

Box A has only blue and orange pens. Probability of choosing a blue or orange pen from Box A is \(P(1)=\frac{9 + 6}{9+6}=1\) (since all pens in Box A are blue or orange).

Step2: Calculate probability of Event 2

Box B has no green pens. Probability of choosing a green pen from Box B is \(P(2)=\frac{0}{8 + 2}=0\)

Step3: Calculate probability of Event 3

Box B has \(8\) blue pens and total \(8 + 2=10\) pens. Probability of choosing a blue pen from Box B is \(P(3)=\frac{8}{10}=0.8\)

Step4: Calculate probability of Event 4

Box A has \(9\) blue pens and total \(9+6 = 15\) pens. Probability of choosing a blue pen from Box A is \(P(4)=\frac{9}{15}=0.6\)

Answer:

Event 2, Event 4, Event 3, Event 1