Question

there is a population of 377 bacteria in a colony. if the number of bacteria doubles every 332 minutes, what will the population be 996 minutes from now? bacteria

Explanation:

Step1: Calculate the number of doubling periods

The number of doubling periods \(n=\frac{996}{332} = 3\)

Step2: Use the formula for exponential growth

The formula for population growth when it doubles is \(P = P_0\times2^n\), where \(P_0 = 377\) (initial population) and \(n = 3\) (number of doubling periods).

Substitute the values into the formula: \(P=377\times2^3\)

First, calculate \(2^3=2\times2\times2 = 8\)

Then, \(P = 377\times8=3016\)

Answer:

\(3016\)