Question

there is a line that includes the point (10, 2) and has a slope of $-\frac{1}{8}$. what is its equation in point - slope form? use the specified point in your equation. write your answer using integers, proper fractions, and improper fractions. simplify all fractions.

Explanation:

Step1: Recall point - slope formula

The point - slope form of a linear equation is $y - y_1=m(x - x_1)$, where $(x_1,y_1)$ is a point on the line and $m$ is the slope of the line.

Step2: Identify values of $x_1$, $y_1$ and $m$

We are given the point $(10,2)$, so $x_1 = 10$ and $y_1=2$. The slope $m=-\frac{1}{8}$.

Step3: Substitute values into the formula

Substitute $x_1 = 10$, $y_1 = 2$ and $m=-\frac{1}{8}$ into the point - slope formula $y - y_1=m(x - x_1)$. We get $y - 2=-\frac{1}{8}(x - 10)$.

Answer:

$y - 2=-\frac{1}{8}(x - 10)$