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question 10
problem reference 6.1
a boy pulls a 10.0 kg sled at a constant velocity for a distance of 18.0 m. he pulls in a direction 38.0° above the horizontal. a 24.0 n frictional force opposes the motion of the sled.
what is the work done by the boys applied, pulling force?
0 j
338 j
549 j
432 j

Explanation:

Step1: Analyze the horizontal force component

Since the sled moves at a constant velocity, the horizontal component of the pulling force \(F_{x}\) equals the frictional force \(f\). So \(F_{x}=f = 24.0\space N\).

Step2: Calculate the work done

The formula for work is \(W = F_{x}d\), where \(d = 18.0\space m\). Substitute the values: \(W=24.0\times18.0\).

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Answer:

432 J