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question 6 of 20
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question 6
problem reference 10.1
a 0.450 kg block is attached to an unstrained horizontal spring with spring constant 74.0 n/m. the block is given a displacement of 0.0800 m and then released from rest.
what is the amplitude of the resulting oscillatory motion?
● 0.0400 m
● 0.0800 m
● 0.160 m
● 0 m
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Explanation:

Step1: Recall amplitude definition

Amplitude is max displacement from equilibrium.

Step2: Identify given displacement

Block is released from 0.0800 m rest, so max displacement = initial displacement.

Answer:

0.0800 m