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question 9 of 20
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question 9
a ball hung from a vertical spring oscillates in simple harmonic motion with an angular frequency of 2.6 rad/s and an amplitude of 0.075 m. what is the maximum acceleration of the ball?
0.13 m/s²
0.20 m/s²
2.6 m/s²
35 m/s²
0.51 m/s²

Explanation:

Step1: Recall max acceleration formula

For simple harmonic motion, $a_{max} = \omega^2 A$

Step2: Substitute given values

$\omega = 2.6\ \text{rad/s}$, $A = 0.075\ \text{m}$
$a_{max} = (2.6)^2 \times 0.075$

Step3: Calculate the result

$(2.6)^2 = 6.76$; $6.76 \times 0.075 = 0.507 \approx 0.51\ \text{m/s}^2$

Answer:

0.51 m/s²