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a circular disk of radius 0.015 m rotates with a constant angular speed of 5.0 rev/s. what is the centripetal acceleration of a point on the edge of the disk?
1.6 m/s²
zero m/s²
0.31 m/s²
15 m/s²

Explanation:

Step1: Convert angular speed to rad/s

$\omega = 5.0 \, \text{rev/s} \times 2\pi \, \text{rad/rev} = 10\pi \, \text{rad/s}$

Step2: Apply centripetal acceleration formula

$a_c = \omega^2 r = (10\pi)^2 \times 0.015$

Step3: Calculate the value

$a_c = 100\pi^2 \times 0.015 \approx 100 \times 9.87 \times 0.015 \approx 14.8 \approx 15 \, \text{m/s}^2$

Answer:

15 m/s²