Question

teks 7.6h: a restaurant offers 3 appetizers, 5 main courses, and 2 desserts. how many different meal combinations (appetizer, main, dessert) are possible?

Explanation:

Step1: Identify the principle

This is a problem of counting combinations using the multiplication principle, which states that if there are \(m\) ways to do one thing, \(n\) ways to do a second thing, and \(p\) ways to do a third thing, then there are \(m\times n\times p\) ways to do all three things together.

Step2: Apply the multiplication principle

Here, the number of ways to choose an appetizer is \(3\), the number of ways to choose a main course is \(5\), and the number of ways to choose a dessert is \(2\). So we multiply these numbers together: \(3\times5\times2\).

Step3: Calculate the result

First, calculate \(3\times5 = 15\), then calculate \(15\times2=30\).

Answer:

30