Question

a tall, heterozygous pea plant (tt) is crossed with another tall, heterozygous pea plant. use a punnett square to determine the probability that the offspring is a short, homozygous pea plant (tt). (1 point) 25% 0% 50% 75%

Explanation:

Step1: Set up the Punnett square

Parents: Tt × Tt.
Possible gametes: T and t from each parent.

$$\begin{array}{|c|c|c|} \hline & T & t \\ \hline T & TT & Tt \\ \hline t & Tt & tt \\ \hline \end{array}$$

Step2: Count the genotypes

There are 4 possible genotypes (TT, Tt, Tt, tt).

Step3: Calculate the probability

Only 1 out of 4 is tt. Probability = $\frac{1}{4}= 0.25 = 25\%$.

Answer:

A. 25%