Question

1. if it takes a bicyclist 0.007 hour to reach a speed of 10 km/hour from rest. she stops after she reaches a speed of 10 km/hour. the acceleration during this period is constant.

a. what is the average speed?
b. what is the distance traveled?

Explanation:

Step1: Calculate average speed

For constant - acceleration motion, the average speed formula is $\bar{v}=\frac{v_{0} + v}{2}$. Here, $v_{0}=0$ (starts from rest) and $v = 10$ km/h.
$\bar{v}=\frac{0 + 10}{2}=5$ km/h

Step2: Calculate distance traveled

Use the formula $d=\bar{v}\times t$. We know $\bar{v}=5$ km/h and $t = 0.007$ h.
$d=5\times0.007=0.035$ km

Answer:

a. The average speed is $5$ km/h.
b. The distance traveled is $0.035$ km.